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A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture isA. `(2//3)T`B. `(8//5)T`C. `(3//5)T`D. `(3//2)T` |
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Answer» Correct Answer - D Temperature of mixture is given by `T=(m_1c_1T_1+m_2c_2T_2)/(m_1c_1+m_2c_2)=(mc2T+(m)/(2)2cT)/(mc+(m)/(2)2c)=(3)/(2)T` |
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