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    				| 1. | A load of 4.0 kg is suspended from a ceiling through a steel wire of radius 2.0 mm. find the tensile stress developed in the wire when equilibrium is achieved. Take `g=3.1pi m/s^-2` | 
| Answer» tension in the wire is `F=4.0x3.1piN` `The area of cross section is `A=pir^2=pix(2.0xx10^-2m)^2` `=4.0pixx10^-6m^2` Thus, the tensile stress developed. `=F/A=(4.0xx3.1pi)/(4.0pixx10^-6)Nm^-2` `=3.1xx10^6Nm^-2` | |