Saved Bookmarks
| 1. |
A loaded truck of mass 3000 kg moves on a level road at a constant speed of 6.00 0 m/s. The frictional force on the truck from the road is 1000 N. Assume that air drag is negligible. (c) What is the total work done by the engine in the full 20 min ? |
|
Answer» Solution :KEY IDEA Adding up the results from (a) and (b) , we can find the total WORK done by engine in 20 minutes. CALCULATIONS: The total work done by the engine in 20 minutes is `W_("tot")= W + W. = 3.600xx 50 J + 5.604 xx 10J` ` = 5.964 xx 10J` or about 60 MJ. |
|