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A long, cylindrical iron core of crosssectional area 5.00 cm^(2) is inserted into a long solenoid having 2000 turns/m and carrying a current 2.00 A. The magnetic field inside the core is found to be 1.57 T. Neglecting the end effects, find themagnetization I of the core and the pole strength developed. |
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Answer» Solution :The magnetic intensity H inside the SOLENOID is `H=ni=2000m^(-1)xx2A=4000A//m` Also `B=mu_(0)(H+I)` or, `I=B/(mu_(0))-H=(1.57T)/(4pixx10^(-7)T-m//A)-4000A/m` `=(1.25xx10^(6)-4000)A//m=1.25xx10^(6)A//m` Note again that the magnetization I > > H for iron core. The pole STRENGTH developed at the ends is `m=IA=(1.25xx10^(6)A//m)xx(5xx10^(-4)m^(2))=625A-m` |
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