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A long one- layer solenoid tightly would of wire with resistivity rho has n turns per unit length. The thickness of the wire insulation is negligible. The cross- sectional radius of the solenoid is equal to a. Find the phase difference betweencurrent and alternating voltagefed to the solenoid with frequency v. |
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Answer» Solution :The current lags behind the voltage by the phase angle `varphi=tan^(-1)((omegaL)/( R))` Now `L=mu_(0)n^(2) pi a^(2)l, l=` LENGTH of the solenoid `R=(rho. 2PI a n .l)/( pi b^(2)), 2B=`diameter of the wire But `2 b n =1 :. B=(1)/(2n)` Then `varphi=tan^(-1)((mu_(0)n^(2)l pi a^(2). 2piv)/( rho. 2pi a n l ))xxpi(1)/( 4n^(2))` `=tan^(-1)((mu_(0)pi^(2) a v)/(4 rhon))` |
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