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A long solenoid has 800 turns per meter length of solenoid. What is the magnetic induction at the end of the solenoid if it carries a current of 2.5A.

Answer»

Solution :`B(mu_0nI)/2=(4pixx10^-7 XX 800 xx 2.5)/2=4pi xx 10^-4=1.256 xx 10^-3 (Wb)/m^2`


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