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InterviewSolution
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A long solenoid with 10 turn / cm and a radius of 7.0 cm carries a current of 20.0 mA .A current of 6.0 A exists in a straight conductor loacted along the central axis of the solenoid at what radial distance from the axis will the direction of the magneitic field be at `45^(@)` to the axial directionA. 4.8 cmB. 8.1 cmC. 9.9 cD. 10.6 cm |
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Answer» Correct Answer - A Given for solenoid n=10 truns /cm `I_(1)=20.0 mA=20xx10^(-3) A` `B_(1)` = magnetic field due to solenoid `B_(2)` = magnetic field due to solenoid ltDbrgt `B_(2)` = magnetic field due to wire for wire `l_(2)=6A` Now according to question if resultant should be at `45^(@)` then the two field `B_(1)` and `B_(2)` must be equal to each other so `B_(1)=B_(2) rarr mu_(0)nl_(1)=(m_(0)l_(2))/(2pir)` `rarr` radius `r=(l_(2))/(l_(1)xxn2pi)` `=(6)/(20xx10^(-3)xx102xx3.14)` `=(6xx10^(2))/(20xx2xx3.14)=(60)/(4xx3.14)` =4.77 =4.8 cm (approx) |
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