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A long straight conductor carrying a current of 2 A is in parallel to another conductor of length 5 cm and carrying a current 3A. They are separated by a distance of 10 cm. Calculate a) B due to first conductor at second b)the force on the short conductor. |
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Answer» Solution :Given `i_1 = 2 A , i_2 =3 A , r =10 cm = 10 xx 10^(-2) m , l_2 = 5 cm ` a) `B = (mu_0 i_1)/(2pi r) = 2 xx 10^(-7) xx (2)/(10 xx 10^(-2)) = 4 xx 10^(-6)` TESLA `b) F = (mu_0 i_1 i_2)/(2pir) xx l_2 = 2 xx 10^(-7) xx (2 xx 3)/(10 xx 10^(-2)) xx 5 xx 10^(-2)` `= 6 xx 10^(-7)` N |
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