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A Long straight conductor carrying a current of 2 A is in parallel to another conductor of length 5 cm. and carrying a current 3A. They are separated by a distance of 10 cm. Calculate (a) B due to first conductor at second conductor (b) the force on the short conductor. |
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Answer» Solution :Given, `i_(1)=2A,i_(2)=3A` `r=10cm=10xx10^(-2)m,l_(2)=5cm` a) `B=(mu_(0)i_(1))/(2pir)=2xx10^(-7)xx2/(10xx10^(2))=4XX10^(-6)` TESLA b) `F=(mu_(0)i_(1)i_(2))/(2pir)l_(2)=2xx10^(-7)xx(2xx3)/(10xx10^(-2))xx5xx10^(-2)` `=6xx10^(-7)N` |
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