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A long straight horizontal cable carries a current of 2.5 A in the direction 10^@ north of east . The magnetic meridian of the place happens to be 10^@ west of the geographic meridian The earth's magnetic field at the location is 0.33 G , ad the angle of dip is zero. Locate the line of neutral points (ignore the thickness of the cable ) (At neutral points , magnetic field due to a current - carrying cable is equal and opposite to the horizontal component of earth's magnetic field ). |
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Answer» Solution :Since the CURRENT is from WEST to east, magnetic lines of FIELD are in the same direction below but in opposite direction above . Al neutral POINT , field of conductor = field of earth i.e., `(mu_0I)/(2pia)=B " or " a = (mu_0I)/(2piB)` 
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