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A long straight wire AB carries a current I.A proton P travels with a speed v, parallel to the wire , at a distance d from it in a direction opposite to the current as shown in figure what is the forceexperienced by the proton and what is its direction? |
Answer» Solution :Magnetic field DUE to current carrying WIRE is perpendicular to plane of paper- downward.  i.e `vecB = - (mu_(0)I)/(2 pi f) hatv` FORCE `vecF = q ( vecv xx vecB) = e [(-v hatj) xx ((mu_(0)I)/(2 pi d) hat v)]` ` = (mu_(0)ev I)/(2 pi d) hati ` That is the magnetic force has magnitude `(mu_(0)e v I)/(2 pi d) ` and is DIRECTED along `+ `ve X - AXIS i.e in the planeof paper perpendicular to direction of `vecv` and to the right. |
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