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A long straight wire carries a current of 35 A. What is the magnitude of the field B at a point 35 cm from the wire ? |
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Answer» SOLUTION :For an EXTREMELY long STRAIGHT thin current carrying wire, magnetic field PRODUCED at perpendicular distance r is, `B=(mu_(0)I)/(2pir)` `thereforeB=((4pixx10^-7)(35))/((2pi)(0.2))` `thereforeB=3.5xx10^(-5)T`
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