1.

A long wire hangs vertically with its upper end clamped, when a torque of 2 Nm is applied to the free end, it is twisted through an angle of 30^(@). Then the potentialenergy of the twisted wire is

Answer»

`PI` joules
`pi//3` joules
`pi//6` joules
`pi//4 ` joules

SOLUTION :`W=(1)/(2) tau theta =(2 xx pi)/(2 xx 6) =(pi)/(6)J`


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