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A long wire with a small current element of length 1 cm is placed at the origin and carries a current of 10 A along the X-axis. Find out the magnitude and direction of the magnetic field due to the element on the Y-axis at a distance 0.5 m from it. |
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Answer» Solution :Here length of current element `DL = 1 cm = 0.01 m, ` current I = 10 A, distance of the point from current element `r = 0.5 m and theta = 90^@` `:.` Magnitude of magnetic FIELD `dB = (mu_0)/(4 pi) (I dl sin theta)/(r^2)` `implies "" dB = (10^(-7) xx 10 xx 0.01 xx sin 90^@)/((0.5)^2) = 4.0 xx 10^(-8) T` The magnetic field ACTS ALONG +z axis. |
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