Saved Bookmarks
| 1. |
A loop ABCDEFA of straight edges has a six corner points A(0, 0, 0), B(5, 0, 0), C(5, 5, 0), D(0, 5, 0), E(0, 5, 5), F(0, 0, 5). The magnetic field in this region is vecB=(3hati + 4hatk)T. The quantity of the flux through the loop ABCDEFA (in Wb) is ...... |
|
Answer» 350  Magnetic FLUX `PHI = vecA.VECB` `therefore phi = (vecA_(x) + vecA_(z))(vecB_(x)+vecB_(z))` `=(25hati + 25hatk).(3hati + 4HATK)` `therefore phi = 175 Wb` |
|