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A loop made of straight edegs has six corners at A(0,0,0), B(L, O,0) C(L,L,0), D(0,L,0) E(0,L,L) and F(0,0,L). Where L is in meter. A magnetic field B = B_(0)(hat(i) + hat(k))T is present in the region. The flux passing through the loop ABCDEFA (in that order) is

Answer»


`B_(0)L^(2)Wb`
`2B_(0)L^(2)Wb`
`sqrt2B_(0)L^(2)Wb`

Solution :Here, `VEC(B)=B_(0)(hat(i)+hat(k))T`

AREA vector of ABCD`=L^(2)hat(j)`
Area vector of DEFA= `L^(2)hat(i)`
TOTAL magnetic flux, `phi=vec(B)*vec(A)`
`=B_(0)(hati+hatk)* L^(2)( hati+hatk)=B_(0)L^(2)(1+1)=2B_(0)L^(2)Wb`


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