Saved Bookmarks
| 1. |
A loop, made of straight edges has six corners at A(0,0,0), B(L,0,0) ,C(L,L,0), D(0,L,0), E(0,L,L) and F(0,0,L). A magnetic field vecB=B_0 (hati+hatk)T is present in the region. The flux passing through the loop ABCDEFA (in that order) is |
|
Answer» `B_0L^2Wb` Area of loop ABCDA in xy-plane , `vecA_1 = |A| hatk =L^2hatk` Area of loop ADEFA in yz- plane `vecA_2=|A|hati =L^2hati` Total area of LOOPS are `vecA=vecA_1+vecA_2` `THEREFORE vecA=L^2hatk+L^2hati` Now flux linked with these loops is `phi=vecA.vecB=(L^2hati+L^2hatk).B_0 (hati+hatk)` where `vecB=B_0 (hati+hatk)` MAGNETIC flux , `phi=vecB.vecA` `=B_0(hati+hatk).L^2(hati+hatk)` `=B_0L^2(1+1)` `=2B_0L^2`
|
|