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A low loss transformer has 250 V applied to primary and gives 4.6 V in secondary. The secondary is connected to a load which draws 5A current. The current flowing in primary is ……… |
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Answer» Solution :`epsilon_1`=250 V, `epsilon_2`= 4.6 , `I_2`= 5A, `I_1` = ? `P_1=P_2` (For an ideal transformer ) `epsilon_1I_1=epsilon_2I_2` `therefore I_1=(epsilon_2I_2)/epsilon_1=(4.6xx5)/250` = 0.092 A `therefore I_1 approx` 0.1 A |
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