1.

(A) M_((g))^(-)toM_((g)) (B) M_((g))toM_((g))^(+) (C) M_((g))^(+)toM_((g))^(2+) (D) M_((g))^(2+) to M_((g))^(3+) minimum and maximum I.P. would be:

Answer»

A,B
B,C
C,D
A,D

Solution :`I.P. prop (+" ve CHARGE")/("-ve charge")`.


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