1.

A [M(H_(2)O)_(6)]^(2+) complex typically absorbs at around 600 n. it is allowed to react with ammonia to form a new compelx [M(NH_(3))_(6)]^(2+) that should have absorption at:

Answer»

800 nm
580 nm
620 nm
320 nm

Solution :As `NH_(3)` is sronger ligand than `H_(2)O`, hence CFSE VALUE for `[M(NH_(3))_(6)]^(3+) gt CFSE` of `[M(H_(2)O)_(6)]^(2+)`
THEREFORE, absorption SHIFTS to smaller wavelength. Also DIFFERENCE between splitting POWER of `NH_(3)` and `H_(2)O` is not very high.


Discussion

No Comment Found

Related InterviewSolutions