1.

A machine gun fires a bullet of mass 40 g with a velocity 1200 ms^(-1). The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fired per second at the most ?

Answer»

One
Four
Two
three

Solution :Here, `F=n(m UPSILON)/(t)`
where n = no. of BULLETS in time t.
`n=(Fxxt)/(m upsilon)=(144xx1)/((40)/(1000)xx1200)=3`
HENCE CHOICE is (d)


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