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A magnet 20 cm long with its polesconcentrated at itsends is palced vertically with itsnorth pole on the table at a pointdue 20 cmif horizontal compoent of the earth 's field is H=0.3 gauss then the polestrength of the magnet is nearly |
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Answer» 1.85 Am Magnetic induction at P due to N pole `=(m)/(20)^(2)` along NO `therefore` Resultantinduction at o at the horizontaldirection `=(m)/(20^(2))-(m)/(20sqrt(2)^(2) cos theta` `=(m)/(400)xx0.6465`  At NEUTRAL point `(m)/(400) xx0.6465=H=0.3` then m=185 ab-A-cm |
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