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A magnet is suspended so that it may oscillate in the horizontal plane. It performs 20 oscillation per minute at a place where the angle of dip is30^@ and 15 oscillations per minute , where the angle of dip is 60^@. Compare the earth's total magnetic field at these two places . |
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Answer» Solution :we known that frequency, `V=(1)/(2PI)sqrt((MB_H)/(I)) or v prop sqrt(B_H) or v prop sqrt(B cos delta)` ` or B? cos delta prop v^(2) or B prop (v^(2))/(cos delta)` `(B_1)/(B_2) = (v_1^(2))/(cos delta_1) xx ( cos delta_2)/(v_2^(2)) = (20 xx 20 xx cos 60^@)/(cos 30^(@) xx 15 xx 15 ) = (16)/(9 sqrt(3))` |
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