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A magnetic dipole is under the influence of two magnetic fields. The angle between the field directions is 60^@, and one of the fields has a magnitude of 1.2 xx 10^(-2) T. If the dipole comes to stable equilibrium at an angle of 15^@ with this field, what is the magnitude of the other field? |
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Answer» Solution :As shown in Fig. Let `vecB_1 =1.2xx10^(-2) T ` and `vecB_2` be inclined at an ANGLE `60^@` from `vecB_1` The magnetic dipole n s COMES to stable equilibrium at an angle of `15^@` with the field `vecB_1`. It means that net torque acting on the magnetic dipole MUST be zero i.e., `vectau_1 + vectau_2 = 0 ` or `|vectau_1 | = |vectau_2|`  `impliesmB_1 sin 15^@ = mB_2 sin (60^@ - 15^@)` `impliesB_1 sin 15^@ = B_2 sin 45^@` `therefore B_2 = (B_1 sin 15^@)/(sin 45^@) =((1.2 xx 10^(-2))xx0.2588)/(0.7071) =4.39 xx 10^(-3) T ~=4.4 xx 10^(-3) T` |
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