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A magnetic dipole of magnetic moment 6 xx 10^(-2)A m^(2) and moment of inertia 12 xx 10^(-6) kg m^(2) performs oscillations in a magnetic field of 2 xx 10^(-2)T. The time taken by the dipole to complete 20 oscillations is (pi = 3) |
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Answer» 36 s Moment of inertia (I) `= 12xx10^(-6)kg m^(2)` Magnetic field (B) `= 2xx10^(-2)T` We know that, TIME (t) `= 2PI sqrt((I)/(MB))` `= 2pi sqrt((12xx10^(-5))/(6xx10^(-2)xx2xx10^(-2)))` `= 2pi sqrt((12xx10^(-2))/(12))` `= 2pi x10^(-1)` For 20 oscillation Time (t) `= 20xx2pi xx10^(-1)=12s` |
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