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A magnetic field is established by a circular current i of radius a. Find the magnetic field gradient (i.e. the derivative of the magnetic field induction vector) in the direction of the circular current's axis at a point whose distance from the centre of the turn is x. |
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Answer» The gradient is `(dB)/(DX) =(mu_(0)p_(m))/(2pi)=d/(dx) (a^2+x^2)^(-3/2)` `=-3/2 (mu_(0)p_m)/(2pi) (a^2+x^2)^(-5//2), 2x=-(3mu_(0) p_(m)x)/(2pir^3)` |
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