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A magnetic field of 5 xx 10^(-5) Tis produced at a perpendicular distance of 0.2 m from a long straight wire carrying electric current. If the permeability of free space is 4 xx 10^(-7)Tm/A The current passing through the wire in A is |
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Answer» 45 ` R = 0.2 m` and ` mu_0 = 4pi xx 10^(-7) mT//A` Magnetic field PRODUCED by long STRAIGHT current (I) carrying wire is given by `B = (mu_0)/(2pi) . I/r rArr 5 xx 10^(-5) = (4 pi xx 10^(-7) )/(2pi) xx (I)/(0.2)` ` rArr I = (5 xx 10^(-5) xx 2pi xx 0.2)/(4pi xx 10^(-7) ) =0.5 xx 10^2 = 50 A` |
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