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A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22^@ with the horizontal . The horizontal component of the earth's magnetic field at the place is known to be 0.35 G . Determine the magnitude of the earth's magnetic field at the place. |
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Answer» SOLUTION :`theta=22^@,H_E=0.35xx10^(-4)T,B_E=`? `H_E=B_Ecostheta,:.B_E=H_E/(COSTHETA)=(0.35xx10^(-4))/(cos22^@)=0.38xx10^(-4)T " or " 0.38 G` |
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