A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north up pointing down at 22^@ with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth's magnetic field at the place.

A magnetic needle free to rotate in a vertical plane parallel to the m

1.	A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north up pointing down at 22^@ with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth's magnetic field at the place.
Answer» Solution : Horizontal COMPONENT of Earth.s magnetic field, `B_(h) B COS PHI` `therefore B= (B_(h) ) /( cos phi) ` `therefore B= (0.35)/( cos 22^(@) )` `therefore B= (0.35) /( 0.9272) ` `therefore B= 0.3775` G (Gauss)

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