1.

A magnetic needle has a magnetic moment of 5 xx 10^(-2) Am^(2) and moment of inertia 8xx10^(-6) kg m^(2). It has a period of oscillation of 2 s in a magnetic field vecB. The magnitude of magnetic field is approximately

Answer»

`3.2 xx 10^(-4) T `
`1.6 xx 10^(-4) T `
`0.8 xx 10^(-4) T `
`0.4 xx 10^(-4 )T `

Solution :`T = 2pisqrt((1)/(mB)) , B = (4 pi ^2I)/( mT^2)`
` B=(4 xx 10 xx 8 xx 10^(-6))/( 5 xx 10 ^(-2)xx 47 ) = 1.6 xx 10^(-3) T `


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