A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30°. Find the horizontal component of earth's magnetic field

A magnetic needle is arranged at the centre of a current carrying coil

1.	A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30°. Find the horizontal component of earth's magnetic field
Answer» Solution :`B=B_(H)TANTHETA(mu_(0)NI)/(2rtantheta)=B_(H)` `B_(H)=(4pixx10^(-7)xx50xx5xx10^(-4)xxsqrt3)/(2XX2(10^(-1))(1))` `=25sqrt3pixx10^(-7)T=1.36xx10^(-7)T`

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