Saved Bookmarks
| 1. |
A magnetised needle of magnetic moment 4.8 xx 10^(-2) Am^(2) is placed at 30^(@) with the direction of a uniform magnetic field of 3 xx 10^(-2)T. If the needle is pivoted through its centre of mass and is free to rotate in the plane of the magnetic field, find the angular frequency of small oscillations. The moment of inertia of the needle about its axis of rotation is 2.25 xx 10^(-5) Kg-m^(2) |
|
Answer» Solution :Angular frequency `, omega=sqrt((MB)/(I))` `= sqrt((4.8 xx 10^(-2) xx 3 xx 10^(-2))/(2.25 xx 10^(-5)))` `= 8 " RAD "s^(-1)` . |
|