1.

A magnetised wire is bent into an arc of a circle subtending an angle 60^(@) at its centre. Then its magnetic moment is X. If the same wire is bent into an are of a circle subtending an angle 90^(@) at its centre then its magnetic moment will be

Answer»

`(xsqrt2)/3`
`x/3`
`((2SQRT2)x)/3`
`(3x)/(2sqrt2)`

Solution :`M^(1)=(2Msin(THETA/2))/theta`


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