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A magnetising field of `1600 Am^(-1)` produces a magnetic flux `2.4 xx 10^(-5)` weber in an iron bar of cross-sectional area `0.2 cm^(2)` . The susceptibility of the iron bar will beA. 1788B. 1192C. 596D. 298 |
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Answer» `mu = (B)/(H) = (phi)/(AH)` `= (2.4 xx 10^(-5))/(0.2 xx 10^(-4) xx 16 xx 10^(2))` `= (2.4 xx 10^(-5))/(16 xx 2 xx 10^(-3))` `= (1.2)/(16) xx 10^(-2)` `(3)/(4) xx 10^(-3)` `= 0.75 xx 10^(-3)` Wb/m A `mu_(r) = (0.75 xx 10^(-3))/( 4 pi xx 10^(-7))` `mu_(r) = (75)/(4pi ) xx 10^(2)` `= 5.9713376` `mu_(r) = 597` `chi_(m) = mu_(r) -1` `chi_(m) = 597-1` `chi_(m) = 596` |
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