A man and a woman appear in an interview for twovacancies in the same post. The probability of mans selection of 1/4 andthat the womans selection is 1/3. What is the probability that none of themwill be selected?

A man and a woman appear in an interview for twovacancies in the same

1.	A man and a woman appear in an interview for twovacancies in the same post. The probability of mans selection of 1/4 andthat the womans selection is 1/3. What is the probability that none of themwill be selected?
Answer» Correct Answer - `1//2` Let `E_(1)` be the events that man will be selected and `E_(2)` the events that woman will be selected. Then, `P(E_(1))=1/4soP(barE_(1))=1-1/4=3/4` `P(E_(2))=1/3,soP(barE_(2))=1-1/3=2/3` Clearly `E_(1)and E_(2)` are independent evets. So, `P(barE_(1)nnbarE_(2))=P(barE_(1))xxP(barE_(2))=3/4xx2/3=1/2`

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A man and a woman appear in an interview for twovacancies in the same post. The probability of mans selection of 1/4 andthat the womans selection is 1/3. What is the probability that none of themwill be selected?

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