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InterviewSolution
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A man can jump vertically through a height 1.5 m on earth. The maximum radius of the planet of the same density as that of earth from whose gravitational field he can escape by jumping is (R_(e )=6400 km) : |
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Answer» Solution :Here square of velocity of man who can jump 1.5 m `=V^(2)=2gh=2xx(GM_(e ))/(R_(e)^(2)xx H)` Square of escape velocity from planet is `v_(e )^(2)=(2GM_(p))/(R_(p))`. Now `v_(e)^(2)=v^(2) therefore R_(p)=sqrt(R_(e )xxh)` if we SUBSTITUTE for velocities `v_(e )` and v and masses in terms of volume `xx` density. Then `R_(p)=sqrt(6400xx10^(3)xx1.5)=3.1xx10^(3)m or =3.1km`. Correct choice is (c ). |
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