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A man fires 10 bullets, each of mass 20 × 10-3 Kg in every second with a gun of mass 10 Kg. If the velocity of each bullet is 300 ms-1, what force must be applied by the man to the gun to hold it in position? If the number of bullets fired per second doubles what will be a new force? |
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Answer» No of bullets, N = 10 Mass of each bullet, M = 20 × 10-3kg ∴ Total mass of 10 bullets, m = N × M = 10 × 20 × 10-3 = 200 × 10-3kg Velocity of each bullet = 300ms-1 From, the equation, F = ma =m\((\frac {v-u}{t})\) = 200 × 10-3 \((\frac {300-0}{1})\) = 60 N ∴ Force required by the man to the gun to hold it in position is 60N. If the number of bullets fired per sec doubles, then force required also doubles. |
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