1.

A man in a balloon rising vertically with an acceleration of 4.9 ms releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is:

Answer»

14.7 m
24.4 m
19.6 m
9.8 m

Solution :Velocity ATTAINED by ball in first 2 second is
`v=u+at=0+4.9xx2=9.8 ms^(-1)`
and height atttained by ballon in first 2 `SEC =(1)/(2) at^(2)`
`:.` Total height GAINED by ball =9.8+4.9=14.7m


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