A man in a balloon rising vertically with an acceleration of 4.9 m/ s – InterviewSolution

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1.	A man in a balloon rising vertically with an acceleration of 4.9 m/ s 2 second after the balloon is let go from the ground the greatest height above the ground reached by the ball is ( g = 9.8 2 )
Answer» a=4.9㎨Initial velocity =0Velocity of balloon and ball after 2 secv=u+at=9.8㎧Height at this pointh= 21 at 2 =0.5×4.9×4=9.8mThe ball will ATTAIN further height =s21 MV 2 =mgss= 2gv 2 =4.9mGreatest height that can be achievedH=h+s=9.8+4.9=14.7mExplanation:HOPE it helps. If it helps mark as brianliest.

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