1.

A man invested 10000 rupees, split into the two schemes, at annual rates of interest 8% and 9%. After one year he got 875 rupees as interest from both. How much did he invest in each?

Answer»

Answer:

2500 rupees is invested at rate of 8% & 7500 rupees is the amount invested at rate of 9%

Step-by-step EXPLANATION:

  • Let x be the amount invested at rate of 8%.
  • Hence 10000-x will be the amount invested at 9%.

We know the relation,

SI=(P×T×R) /100

here,

  • SI = SIMPLE Interest
  • P = Principal Amount
  • T = Time
  • R = Rate of Interest

For the first one,

SI = (x × 1 × 8)/100

For the second one,

SI=[(10000-x) × 1 × 9]/100

Also given,

  • He got 875 rupees as interest on both investments.

(8x/100) + ((10000-x) × 9/100) = 875

On solving this,

we GET x = 2500 and 10000-x = 7500

∴ 2500 rupees is invested at rate of 8% & 7500 rupees is the amount invested at rate of 9%


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