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A man invests rupees 5600 at 14% per annum ci for 2 years. calculate:(1)the interest for the first year.(2)the amount at the end of the first year.(3)the interest for the second year, correct to the nearest rupee |
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Answer» Answer: i hope this will help u plz mark this as brainliest Step-by-step explanation: For the first year: P= RS. 5,600, N=1 year and R=14% We have S.I. = 100 PNR = 100 5,600×1×14 = Rs. 784 And Amount at the end of first year P+S.I.= Rs. 5,600+ Rs. 784= Rs. 6,384 Now, for the SECOND year : P= Rs. 6,384, N=1 year and R=14% We have S.I.= 100 PNR = 100 6,384×1×14 = Rs. 893.76 To the nearest rupee, it is Rs. 894. |
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