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A man is 4 times as old as his son. After four years the man will be thrice as old as his son find their present ages |
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Answer» present AGES of man and son be 'x' and 'y'After 4 years : Age of man = x + 4Age of son = y + 4From the DATA , x = 4Y .... (i)(x + 4) = 3(y + 4)x + 4 = 3y + 12 .... (ii)Substituting x = 4y in EQ(ii) , x + 4 = 3y + 12 4y + 4 = 3y + 124y - 3y = 12 - 4y = 8Substituting y = 8 in x = 4yx = 4y:. x = 4(8) = 32Present age of man = 32Present age of son = 8 |
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