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A man is at a distance from the bus: when the bus begins to move with a constant acceleration 'a', with what minimum velocity the man should run towards the bus so as to catch it? |
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Answer» `SQRT(2ax)` Distancecovered by the man=vt `:. X+(1)/(2)at^(2)-vt+x=0` or `t=(vpmsqrt(v^2-2ax))/(a)` Now t is real when `sqrt(v^(2)-2ax)` is +ve and its minimum VALUE is Zero. `:. V^2-2ax=0` or `v=sqrt(2ax)` |
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