1.

A man is at a distance from the bus: when the bus begins to move with a constant acceleration 'a', with what minimum velocity the man should run towards the bus so as to catch it?

Answer»

`SQRT(2ax)`
2ax
`sqrt(ax)`
ax

Solution :Here `X+(1)/(2)at^(2)` =Distance to be covered.
Distancecovered by the man=vt
`:. X+(1)/(2)at^(2)-vt+x=0`
or `t=(vpmsqrt(v^2-2ax))/(a)`
Now t is real when `sqrt(v^(2)-2ax)` is +ve and its minimum VALUE is Zero.
`:. V^2-2ax=0` or `v=sqrt(2ax)`


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