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A man is throwing balls in air. He throws next ball when previous one is at the highest point. If he throws each ball after 2s , then height to which ball rises is |
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Answer» 10 m v= u+at `:.0=u-gxx2` or `u=2xx10=20 ms^(-1)` ALSO `h=(v^(2)-u^2)/(2a)=(0-400)/((-10)xx2)=20 m` |
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