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A man measures the period of a simple pendulum inside a stationary lift and finds it to be T sec. if the lift accelerates upwards with an acceleration g/4, then the period of the pendulum will beA. `T`B. `T/4`C. `(2T)/(sqrt(5))`D. `2Tsqrt(5)` |
Answer» Correct Answer - C `(T_(1))/(T_(2))=sqrt((g+g/4)/g)=(sqrt(5))/2` `T_(2)=(2T)/(sqrt(5))` |
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