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A man moving on track ABC, getting rain drops vertical for the path AB, and along same line of its motion for path BC then actual speed of rain drop is |
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Answer» `10sqrt3ms^(-1)` For path AB `V_(x) = 5 ms^(-1)` For path BC velocity of rain `_|_r` to BC should be zero hence `V_(x)sin30^(@) = V_(y)COS30^(@) V_(y) = (5)/(sqrt3)ms^(-1)` `V_(R ) = sqrt(V_(x)^(2)+V_(y)^(2))= (10)/(sqrt3)ms^(-1)` |
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