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InterviewSolution
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A man of `50 kg` mass is standing in a gravity free space at a height of `10m` above the floor. He throws a stone of `0.5 kg` mass downwards with a speed `2m//s`. When the stone reaches the floor, the distance of the man above the floor will beA. `20m`B. `9.9m`C. `10.1m`D. `10m` |
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Answer» Correct Answer - c Here, `m_(1) = 50 kg, m_(2) = 0.5kg, upsilon_(2)m//s` `S = 10 m, upsilon_(1) =`? From the coservation of liner momentum `m_(1) upsilon_(1) = m_(2) upsilon_(2)` Therefore `50 xx upsilon_(1) = 0.5 xx 2` `upsilon_(1) = (1)/(50)m//s` Time taken by the stone to cover the distance of `10m` and reach the floor (in gravity free space) ` t = (S)/(upsilon_(2) = (10)/(2) =5s` distance covered by the man (in the opposite direction) in `5 sec = upsilon_(1) xx t = (1)/(5) xx 5 =0.1m` Distance of the man above the floor `= 10+ 0.1 = 10.1m` . |
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