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A man of `50 kg` mass is standing in a gravity free space at a height of `10m` above the floor. He throws a stone of `0.5 kg` mass downwards with a speed `2m//s`. When the stone reaches the floor, the distance of the man above the floor will beA. 9.9 mB. 10.1 mC. 10 mD. 20 m |
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Answer» Correct Answer - B Let distance of man from the floor be (10+x) m. As centre of mass of system remains at 10 m above the floor. So `50 (x ) =0.5 (10)implies x=0.1m` `implies `Distance of the man above the floor =10+0.1 |
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