1.

A man of 55 kg is holding a bucket of mass 25 kg. He walks 50 m on a level road at a constant speed of 3 ms" and then climbs up a hill of height 20 m. What is the work done by the man ?

Answer»

16 KJ
12 KJ
3.5 KJ
2 KJ

Solution :While walking WORK done is zero as FORCE and displacement are `bot` to each other and there is no net force along HORIZONTAL as the speed is constant.
`:.` work is done in climbing the hill.
`W=(M+m)gh=(55+25)xx10xx20=16000 J`
= 16 J


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