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A man of height H is standing in front of an inclined plane mirror at an angle `theta` from horizontal. The vertical separation between man and inclined plane is x. Man can see its complete image in length `(H(H+x)"sin"theta)/(H +2x)` of mirror . (Given : x = H = 1m and `theta = 45^(@)`) If man starts moving with velocity `sqrt(2)ms^(-1)` along inclined plane, find out length of mirror at t = 1s in which he can see his complete image,A. `(sqrt(2))/(3)m`B. `(2)/(3)`C. `(1)/(3)m`D. `(1)/(3sqrt(2))m` |
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Answer» Correct Answer - A In this case x, H and `theta` remains same so required length of mirror = `(H(H+x)"sin"theta")/(H + 2x)` =`(1(1+1)"sin"45^(@))/(1 + 2 xx1) = (sqrt(2))/(3)m` |
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